Question

what is the sum which when divided among x, y, z in proportion 3:5:7 provides 8000 more to z than what it would have done to him when proprtion is 11:15:19
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Answer 1

Step-by-step explanation:

If a Sum A is divided into three parts in the proportion 3:5:7 or (a:b:c) then

X=(a/a+b+c)A

X=3/3+5+7*A

X=3/15A

Y=(b/a+b+c)A=5/15A

Z=(c/a+b+c)A=7/15A

For e:f:g or (11:15:19) then

X = 11/45A

Y = 15/45A

Z = 19/45A

19/45A = 7/15A - 8000

7/15A - 19/45A = 8000

2/45A = 8000

A = 180000

Answer 2

Given :- what is the sum which when divided among x, y, z in proportion 3:5:7 provides 8000 more to z than what it would have done to him when proprtion is 11:15:19 ?

Solution :-

Let us assume that, the total sum is S.

now given that, the sum is divided among x, y, z in proportion 3:5:7.

So,

→ share of z = [7 out of (3 + 5 + 7)] of total sum.

→ share or z = (7/15) of S = Rs.(7S/15) .

now, we have given that, z got Rs.8000 more if the sum is divided among x, y, z in proportion 11 : 15 : 19.

So,

→ New share of z = [19 out of (11 + 15 + 19)] of total sum.

→ New share of z = (19/45) of S = Rs.(19S/45).

Therefore,

→ old share of z - New share of z = Rs.8000

→ (7S/15) - (19S/45) = 8000

→ (21S - 19S) /45 = 8000

→ (2S/45) = 8000

→ 2S = 8000 * 45

dividing both sides by 2,

→ S = 4000 * 45

→ S = Rs.180000

Hence, Total sum is Rs.180,000 .

Learn more :-

If (x+10)% of 240 is 60% more than x% of 180. then 15% of (x+20) is what percent less than 25% of x?

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