What is the surface area of a hollow cylinder with outer radius 4cm,inner radius 3cm and height 5cm
Answers
Answered by
2
Answer:
263.8938 sq. cm
Step-by-step explanation:
R1 = 3 cm
R2 = 4 cm
h = 5 cm
Surface area of hollow cylinder = 2(pi)(R1)h + 2(pi)(R2)h + 2(pi)[{(R2)^2} - {(R1)^2}]
= 263.8938 sq. cm
Answered by
1
Answer:
264cm^2 ( important)
Step-by-step explanation:
let outer radius R = 4cm, inner radius
r = 3cm & height h = 5cm
total surface area of hollow cylinder
= 2π(R + r) (R - r + h)
= 2*22/ 7 (4 + 3) ( 4 - 3 + 5)
= (44/7) * 7 * 6 = 264 cm^2
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