Question

What is the surface area of a hollow cylinder with outer radius 4cm,inner radius 3cm and height 5cm

Answer 1

Answer:

263.8938 sq. cm

Step-by-step explanation:

R1 = 3 cm

R2 = 4 cm

h = 5 cm

Surface area of hollow cylinder = 2(pi)(R1)h + 2(pi)(R2)h + 2(pi)[{(R2)^2} - {(R1)^2}]

= 263.8938 sq. cm

Answer 2

Answer:

264cm^2 ( important)

Step-by-step explanation:

let outer radius R = 4cm, inner radius

r = 3cm & height h = 5cm

total surface area of hollow cylinder

= 2π(R + r) (R - r + h)

= 2*22/ 7 (4 + 3) ( 4 - 3 + 5)

= (44/7) * 7 * 6 = 264 cm^2