What is the surface area of a pipe 48 inch diameter 500 feet long?
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given, diameter = 48 inch
radius = 24 inch = 2 feet
the pipe is always cylindrical so length is equal to height = 500 feet
surface area = 2πrh
= 2×3.14 ×2×500
= 6280 square feet
therefore surface area = 6280 square feet
radius = 24 inch = 2 feet
the pipe is always cylindrical so length is equal to height = 500 feet
surface area = 2πrh
= 2×3.14 ×2×500
= 6280 square feet
therefore surface area = 6280 square feet
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