What is the surface area of a sphere if the volume is 3000 pi
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Answer:
volume of a sphere of radius r unit is
4πr^3/3
according to question,
4πr^3/3=3000π
=> r^3=3000×3/4
=> r^3=9000/4
=> r^3=2250
=> r^3=3×5×3×5×2×5
=> r=5cube root of 18=5(18)^1/3
so, surface area
=4πr^2
=4π(5 cube root of 18)^2
=100π(18)^2/3
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