Math, asked by gsrobbins07, 10 months ago

What is the surface area of a tissue box with a length of 8 inches, a width of 4 inches and a height of 3 inches?

Answers

Answered by nagangouda1974
2

Step-by-step explanation:

c.s.a of Cuboid= 2(lb+hb+hl)-lb

= 2(8×4+3×4+3×8)-8×4

= 2(32+12+24)-32

= 2(68)-32

= 136-32

=. 104

Answered by shafffu
1

1 inch is equal to 2.5 cm

8inches is 8*2.5=20cm

4inches =4*2.5=10cm

3inches=3*2.5=7.5cm

surface area= (lb+bh+hl)

(20*10+10*7.5+7.5*20)

(200+75+150)

=425cm²

i think ur happy with my answer

plzzz mark as brainliest

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