Question

what is the surface area of cylinder whose diameter is 40cm and height is 14 cm​

Answer 1

Answer:A≈4272.57cm²

d Diameter  

40

cm

h Height  

14

cm

Step-by-step explanation:A=2πd

2h+2π(d

2)2=2·π·40

2·14+2·π·(40

2)2≈4272.56601cm²

Answer 2

Step-by-step explanation:

d=40cm=r=d/2=20cm

h=14cm

Surface area= L.S.A. of cylinder

= 2×22/7×20×14

= 2×22×2×20

= 44×40

= 1760cm^2