Question

What is the surface tension of a square of length 60 cm soap film if it experiences a net force of 0.6N.​

Answer 1

Answer:

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Explanation:

Here, S=0.06Nm

−1

,r

1

=2cm=2×10

−2

m,

r

2

=5cm=5×10

−2

m

Since bubble has two surfaces, initial surface area of the bubble

=2×4πr

1

2

=2×4π×(2×10

−2

)

2

=32π×10

−4

m

2

Final surface area of the bubble

=2×4πr

2

2

=2×4π×(5×10

−2

)

2

=200π×10

−4

m

2

Increase is surface area = 200π×10

−4

−32π×10

−4

=168π×10

−4

m

2

Work done = surface tension × increase is surface area

=0.06×168π×10

−4

=3.12×10

−3

J=3.12mJ