Question

What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm?
Use P V equals n R T. and R equals 0.0821 StartFraction L times atmospheres over moles time K EndFraction..

Answer 1

Answer:

Explanation:

from,

PV=nRT

p=2.21atm

V=6850ml(=6.85L)

n=0.750mol

R=0.0821atmL/mol K

T=(2.21×6.85)÷(0.750×0.0821)

T=245.9K