What is the temperature of 1 mole of an ideal gas varies with its volume, maximum pressure?
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Answer:
Explanation:
From
PV = RT
we get T = PV/R put in T = –V3 + V2,
PV/R = -aV^3 + bV^2
P = R(-aV^2 + bV)
dP/dV = 0 = R(-2aV + b) = 0
V = b/2a
Put in Pressure value we get,
P = R(-a*b^2/4a^2 + b*b/2a) = > R(b^2/2a – b^2/4a)
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