Question

What is the temperature of gas given 60.06 liters, 8.65 mol and 16 atm?

Answer 1

Answer:

The ideal gas equation relating pressure (P), volume (V), and absolute temperature (T) is given as:

PV = nRT

Where,

R is the universal gas constant =8.314Jmol

−1

K

−1

n = Number of moles = 1

T = Standard temperature = 273 K

P = Standard pressure = 1 atm =1.013×10

5

Nm

−2

∴V=nRT/P

=1×8.314×273/(1.013×10

5

)

=0.0224m

3

=22.4 litres

Hence, the molar volume of a gas at STP is 22.4 litres.