Question

What is the temperature of gas given 60.41 liters, 8.03 mol and 3 atm?
How do I solve this?, What is the answer?

Answer 1

Explanation:

• Volume V = 60.41 litres
• Moles n = 8.03 mols
• Pressure P = 3 atm
• Temperature T = ?
• Universal Gas Constant R = 0.082 L atm mol-¹ K-¹

By ideal gas equation :-

PV = nRT

T = PV / nR

$= \frac{3 \times 60.41}{8.03 \times 0.082}$

$= \frac{181.23}{0.654}$

= 277.11 K