What is the tensile stress if a square rod of 10mm side is tested for a tensile load of 1000 kg ?
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Answer:
98.1 N/mm²
Step-by-step explanation:
Tensile load,F = Mg
= 1000*9.81
= 9810 N
Here I assumed that the load is applied by a 1000kg mass on earth.
Cross section area of the rod is given by
A = 10*10 mm²
= 100 mm²
Tensile stress on the rod is given by
σ = F/A
= 9810/100 N/mm²
= 98.1 N/mm²
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