Question

What is the tenth term of the geometric sequence with a4 = 16 and r = 2?

Answer 1

Solution:

Let a , r are first term and common ratio of a G.P.

$\boxed { a_{n} = ar^{n-1}}$

Here, it is given that,

$a_{4} = 16 \: and \: r = 2$

=> ar³ = 16

=> a×2³ = 16

=> a × 8 = 16

=> a = 16/8

=> a = 2

Now ,

10 th term

= $a_{10} = ar^{9}$

= $2\times 2^{9}$

= $2^{10}$

= $1024$

••••

Answer 2

Answer:

Step-by-step explanation: