Question

What is the the pressure at a depth of 15cm in brine of density 1.2g/cm³?Take g=10ms-²

Answer 1

Answer:

The pressure at the depth of 15 cm is 1.8×10³ Pa

Step By Step Solution:

Depth (d) = 15 cm = 0.15 m

Density of the brine solution = 1.2 g/cm³

                                                 = 1.2×10³ kg/m³

The pressure at depth d from the surface of the liquid is given by the formula

Pressure = depth × density of liquid × g

=> P = d×ρ×g

By substituting the given values in the above formula, we get

=> P = d×ρ×g

=> P = 0.15 × 1.2×10³ × 10

=> P = 1.8×10³ Pa

$\boxed{{\text{The pressure at the depth of 15 cm is 1}}{\text{.8}} \times {\text{1}}{{\text{0}}^3}{\text{ Pa}}}$