Question

What is the the value of t, if
6(t+3)=5(2t-2) *​

Answer 1

Hope it is helpful....

Answer 2

Answer:

$t= 7$

Step-by-step explanation:

Step 1: Simplify  both sides of the equation.

6(t+3)=5(2t−2)

(6)(t)+(6)(3)=(5)(2t)+(5)(−2)(Distribute)

6t+18=10t+−10

6t+18=10t−10

Step 2: Subtract 10t from both sides.

6t+18−10t=10t−10−10

−4t+18=−10

Step 3: Subtract 18 from both sides.

−4t+18−18=−10−18

−4t=−28

Step 4: Divide both sides by -4

$\frac{-4t}{-4}=\frac{-28}{-4}$

t = 7