what is the third derivative of x/√1-x^2
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y = x/√(1-x²)
Apply the rule for differentiation of u/v:
dy/dx = [ √(1-x²) * 1 - x * {-2x/2√(1-x²) } ] / (1-x²)
= [1 - x² + x² ] /(1-x²)³/²
= 1/(1-x²)³/²
d²y/dx² = -3/2 * 1/(1-x²)⁵/² * (-2x)
= 3x /(1-x²)⁵/²
d³y/dx³ = 3 * [(1-x²)⁵/² - x * 5/2 * (1-x²)³/² (-2x) ] / (1-x²)⁵
= 3 * (1-x²)³/² * [ 1 - x² + 5 x² ] / (1-x²)⁵
= 3 (1 + 4 x²) / ( 1 - x²)⁷/²
Apply the rule for differentiation of u/v:
dy/dx = [ √(1-x²) * 1 - x * {-2x/2√(1-x²) } ] / (1-x²)
= [1 - x² + x² ] /(1-x²)³/²
= 1/(1-x²)³/²
d²y/dx² = -3/2 * 1/(1-x²)⁵/² * (-2x)
= 3x /(1-x²)⁵/²
d³y/dx³ = 3 * [(1-x²)⁵/² - x * 5/2 * (1-x²)³/² (-2x) ] / (1-x²)⁵
= 3 * (1-x²)³/² * [ 1 - x² + 5 x² ] / (1-x²)⁵
= 3 (1 + 4 x²) / ( 1 - x²)⁷/²
kvnmurty:
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Here's your answer friend,
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@#shakti37
Refer to the attachment.
Hope it's useful and helpful!!!
@#shakti37
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