Question

What is the third ionization energy(l.Es) of lithium atom in electron volt unit?
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Answer 1

Answer:

IP= -E= 13.6 × Z²/ n² ( where z= atomic number, n= orbit )

For Li⁺², we have Z= 3, n= 1 as two IPs are already required to make it a hydrogen- like atom.

Therefore IP= 13.6× 9/4

Your answer is correct. Well done.