Question

what is the third sequence of The sum of 5 consecutive odd numbers is 145.

Answer 1

let the numbers be x,x+2,x+4,x+6,x+8
x+x+x+x+x=145-2-4-6-8
x+x+x+x+x=145-20
5x=125
x=125/5
x=25
x+2=25+2=27
x+4=25+4=29
x+6=25+6=31
x+8=25+8=33

Answer 2

Answer:

29

Step-by-step explanation:

We know that consecutive odd numbers have a difference of 2 between them

∴ Lets 5 consecutive odd numbers be

x, x + 2, x + 4, x + 6, x + 8

According to Question

Sum of these five odd numbers = 145

∴ x + ( x + 2) + ( x + 4) + (x + 6) + (x + 8) =145

5x + 20 = 145

5x = 125

x = 25

∴ Desired numbers are 25, 27, 29, 31, 33

and Third Sequence is 29