Question

What is the third side of the triangle if one side of the triangle is 56cm and second 64cm and the whole perimeter is 180 ??
Help me

Answer 1

Given :

• First Side $\leadsto$ 56cm
• Second Side $\leadsto$ 64cm

To find :

• We have to find the Third Side of the Triangle

Solution :

First we have to add the First and Second Side then we will subtract 180° by the addition of the both the sides So, we will get the Third Side , So now let's solve!

$\;\boxed{\sf{\purple{Sum \: of \: the \: length \: of \: all \: sides \: of_{\:(triangle)} = 180 \degree }}}$

$: \implies \sf \: First \: side \: + Second \: side \\ \\ \\ : \implies \sf \: 56cm \: + \: 64cm \\ \\ \\ : \implies \: \sf 120 \: cm \\ \\ \\ \therefore {\sf {\underline {Now \: we \: will \: find \: the \: third \: side}}} \\ \\ \\ : \implies \sf 180 \: - 120 \\ \\ \\ \: \: \: \: \: \: \: \: \: : \implies \: { \underline{ \boxed{ \pink{ \mathfrak{60 \: cm}}}}}$

Verification :

$: \implies \sf 56cm \: + 64cm \: + 60cm \\ \\ \\ : \implies{ \underline{ \boxed{ \pink{ \mathfrak{180 \degree}}}}}$

•°• Hence, verified! that the third side of Triangle $\leadsto$ 60cm

Diagram :

[Note :- See the Diagram in the attachment]

⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀

Answer 2

Answer:

$\bf\red{Question}$

What is the third side of the triangle if one side of the triangle is 56cm and second 64cm and the whole perimeter is 180 ?

$\bf\red{Given}$

One side = 56 cm

Second Side = 64 cm

Perimeter of triangle = 180

$\bf\red{To\:find}$

• We have to find the the third side of the triangle which is x.

$\bf\red{Formula}$

Area of ∆ = Sum of length of three sides of triangle.

$\bf\red{Solution}$

One side = 56 cm

Second Side = 64 cm

Perimeter of triangle = 180

Area of ∆ = Sum of length of three sides of triangle.

•°• The third side is:-

56 + 64 + x = 180

120 + x = 180

x = 180 - 120

x = 60

•°• Third side is x = 60 cm

$\bf\red{Verification}$

56 + 64 + x = 180

Here the x is 60

56 + 64 + 60 = 180

180 = 180

Hence Proved

LHS = RHS

x = 60 cm

Diagram :- The diagram for the above question is in attachment. Please Refer.