Question

what is the third side of traingle where third side is 12cm and 16 cm.​

Answer 1

let the 3rd side be x

$= > {x}^{2} = {12}^{2} + {16}^{2} \\ \\ = > {x}^{2} =144 + 256 \\ \\ = > {x}^{2} = 400 \\ \\ = > x = \sqrt{400} \\ \\ = > x = 20 \: cm$

Answer 2

some information is missing in your questions,

it can be anything greater than 4 & less than 28

4 < third side value< 28

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