what is the third term in b2+26b+________ to form a perfect square trinomial.
Answers
Answered by
5
13^2
Now
It is
b^2 + 2.(b).(13) + 13^2
Now
It is
b^2 + 2.(b).(13) + 13^2
Answered by
0
The third term is 13², b² +26b+ 13² is the perfect square trinomial.
GIVEN:- b²+26b+...
TO FIND:- The third term in b²+26b+
SOLUTION:-
- An expression attained from the squaring of the binomial equation is a perfect square trinomial.
- If a trinomial is in the form ax² + bx + c then it is known to be a perfect square which is possible if and only if it satisfies the condition b² = 4ac.
According to the question,
- Applying (a + b)² = a² + 2ab + b²
2 × first term × third term = second term
We already know the first term so we won't include it
2 × third term = 26
Third term = 26/2 = 13
Prove
b² + (2 × b × 13) + 13²
= b² + 26b + 13²
Hence, the third term is 13², b² +26b+ 13² is the perfect square trinomial.
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