What is the time period of a pendulum of length 9.8 m?
Answers
Answered by
25
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⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
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Let, T = Time period, l = length of pendulum and g = acceleration due to gravity.
We know that, l = 9.8 m & g = 9.8 m/s²
Then, by formula,
T = 2 π √(l/g)
=> T=2×22/7×√(9.8/9.8)
=> T = 44/7 × 1
=> T = 44/7 seconds
=> T = 6.28 seconds [REQUIRED ANSWER]
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⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Let, T = Time period, l = length of pendulum and g = acceleration due to gravity.
We know that, l = 9.8 m & g = 9.8 m/s²
Then, by formula,
T = 2 π √(l/g)
=> T=2×22/7×√(9.8/9.8)
=> T = 44/7 × 1
=> T = 44/7 seconds
=> T = 6.28 seconds [REQUIRED ANSWER]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
Answered by
12
Let, T = Time period, l = length of pendulum and g = acceleration due to gravity.
We know that, l = 9.8 m & g = 9.8 m/s²
Then, by formula,
T = 2 π √(l/g)
=> T=2×22/7×√(9.8/9.8)
=> T = 44/7 × 1
=> T = 44/7 seconds
=> T = 6.28 seconds [REQUIRED ANSWER]
We know that, l = 9.8 m & g = 9.8 m/s²
Then, by formula,
T = 2 π √(l/g)
=> T=2×22/7×√(9.8/9.8)
=> T = 44/7 × 1
=> T = 44/7 seconds
=> T = 6.28 seconds [REQUIRED ANSWER]
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