what is the torque of the force f=2i-5j+4k m acting at the point r=3i+3j+3k m about the origin
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Answered by
5
Anser is 0 Nm.
Explanation:
we know that torque=F×r
where F×r means Fr sin theta.
we have F=2i+5j+4k
and. r=3i+3j+3k
theta =0. ( becouse in the question they gave us theta is about the origin)
substitute the values in the formula
torque=(2i+5j+4k)(3i+3j+3k)0 Nm.
therefore torque becomes 0 Nm.
The units for torque are Nm.
Additional information: torque is also known as moment of force.
Hope this will help you.
Answered by
2
Answer:
hey fine Didi
how are you???
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