Physics, asked by AyushLokhande1633, 11 months ago

What is the torque required to hold a small circular coil of 10 turns, area 1 mm​2 and carrying a current of (31/53) in the middle of a long solenoid of 10​4 turns/meter carrying a current of 3.5 A, with its axis perpendicular to the axis of the solenoid?

Answers

Answered by Ambarsariya
0

Explanation:

Torque = F*r*sin(theta)

where, F is force

R is radius

Sin(theta) is the angle

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