What is the total angular displacement of a particle in ucm of frequency 65hz in 5 second
Answers
Answered by
0
Answer:
325 ucm
Explanation:
frequency/second
Answered by
1
The angular displacement of the particle in uniform circular motion is 650π rad.
We have to find the total angular displacement of a particle in uniform circular motion of frequency 65 Hz in 5 sec.
Angular velocity, ω = 2πη
Where η is angular frequency.
∴ ω = 2π × 65 = 130π rad/s
We know,
Angular displacement, θ = ωt
Here, ω = 130π , t = 5 sec
∴ θ = 130π × 5 = 650π rad
Therefore the angular displacement of the particle in uniform circular motion is 650π rad.
Similar questions