What is the total delay (latency) for a frame of size 5 million bits that is being sent on a link with 10 routers each having a queuing time of 2 Ils and a processing time of 1 Ils. The length of the link is 2000 Km. The speed of light inside the link is 2 x 108 mls. The link has a bandwidth of 5 Mbps. Which component of the total delay is dominant? Which one is negligible?
Answers
Answered by
30
Answer:
Explanation:
Propagation time = distance / propagation speed
= 2000 Km / 2 x 108 m/s = 10 ms
Transmission time = Message size / Bandwidth
= 5 x 106 bits/ 5 Mbps = 1 s
Queuing time = 10 routers * 2 us = 20 us
Processing Delay = 10 routers * 1 us = 10 us
Total delay (latency) = 10 ms + 1 s + 20 us + 10 us
= 1010.03 ms = 1.01003 s / 1 s
Answered by
3
Answer:
Answer: Propagation time = distance / propagation speed = 2000 Km / 2 x 1018 m / s = 10 ms Transmission time = Message size / Bandwidth = 5 x 10 ^ 6 bits /.
Explanation:
Similar questions