What is the total delay (latency) for a frame of size 50 million bits that are being sent on a link with 35 routers each having a queuing time of 3 micro second and processing time of 2 micro second. The length of the link is 12000 Km. The speed of light inside the link is 2 x 10 power 8 m/s. The link has a bandwidth of 15 Mbps.
Answers
Answer:
1.01000030 s
Step-by-step explanation:
Given,
Frame of size = 5 million bits = 5 × bits = 5000000 bits
Queuing time = 2 μs = 2 × sec = 0.000020 sec
Processing time = 1 μs = 1 × sec = 0.00001 sec
Length of link, distance d = 2000 Km = 2000 × m
The speed of light (Propagation speed) =
Bandwidth , B = 5 Mbps = 5 × bps
For delay (latency), use the following formula
Delay (latency) = Propagation time + Transmission time + Queuing time + Processing time ...........(i)
Propagation time =
=
= 0.01 sec
Transmission time =
=
= 1 sec
Now, from equation (i) we get,
Delay (latency) = 0.01 + 1 + 0.000020 + 0.000010
= 1.010030 sec
Explanation: