Chemistry, asked by dhanabarnishtha, 6 hours ago

what is the total electron content of the species Mg2+ and O2- ? Nme 5 more such speceis.​

Answers

Answered by kyungjayi456
1

Answer:

Mg²⁺ = 10 electrons

O²⁻ = 10 electrons

Other elements with 10 electrons: N³⁻,  F⁻,  Ne,  Na⁺,  Al ³⁺

Explanation:

The elements and ions that have the same number of electrons are known as isoelectronic species

The ions that are formed by removing electrons are known as cations. They are positively charged

The ions that are formed by gaining electrons are known as anions. They are negatively charged

The electronic configurations of the above elements and ions are given below

N = 1s² 2s²2p³

N³⁻ = 1s² 2s²2p⁶

O = 1s² 2s²2p⁴

O²⁻ = 1s² 2s²2p⁶

F = 1s² 2s²2p⁵

F⁻ = 1s² 2s²2p⁶

Ne= 1s² 2s²2p⁶

Na = 1s² 2s²2p⁶ 3s¹

Na⁺ = 1s² 2s²2p⁶

Mg = 1s² 2s²2p⁶ 3s²

Mg²⁺ = 1s² 2s²2p⁶

Al = 1s² 2s²2p⁶ 3s²3p¹

Al³⁺ = 1s² 2s²2p⁶

Please ignore the explanation if you haven't learnt in this method. I explained this according to the way I have learnt.

Hope it helps you in some way

Answered by Prince063867
0

Answer:

The electronic configurations of the above elements and ions are given below

N=1s² 2s²2p³

N³-=1s²2s²2pº

O=1s² 2s²2p4

0²-=1s²2s²2p

F = 1s² 2s²2p5

F-=1s² 2s²2p

Ne=1s² 2s²2pº

Na 1s² 2s²2p 3s¹

=

Na+ = 1s² 2s²2p⁰

Mg = 1s² 2s²2p 3s²

Mg²+ = 1s² 2s²2pº

Al = 1s² 2s²2p 3s²3p¹

Al³+ = 1s² 2s²2pº

Please ignore the explanation if you haven't learnt in this method. I explained this according to the way I have learnt.

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