Question

What is the total kinetic energy of 2g of Nitrogen gas at temperature 300 K. ​

Answer 1

Answer:

Given, mass of Nitrogen gas =2g

MW=28,T=300K,

R=8.31×107 erg mol−1K−1

Kinetic energy of 2g of N2=2×3/2RT/MW = 3RT/MW

=3×8.31×107×300 / 28erg=267×10^7erg

the total kinetic energy of 2g of Nitrogen gas at temperature 300 K =267×10^7erg

Answer 2

Concept:

The average kinetic energy of gas particles, as predicted by the kinetic molecular theory, is inversely correlated with the absolute temperature of the gas.

Given:

Temperature= 300K

Mass of Nitrogen gas= 2g

To find:

Total Kinetic Energy

Solution:

Molecular weight of 2g Nitrogen will be 28.

$R= 8.314 \times 10^{7} erg mol^{-1} K^{-1}$

$Kinetic Energy = 2 \times \frac{3}{2} \frac{RT}{M_{w} } = 3\frac{RT}{M_{w} } \\= \frac{3 \times 8.31 \times 10^{7} \times 300}{28}$

$= 267 \times 10^{7} erg$

The total kinetic energy for 2g of nitrogen is $267 \times 10^{7} erg$.

 

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