Question

What is the total mass of 3.01 x 1023 atoms of helium gas

Answer 1

Answer:

Well Avogadro's number of helium atoms has a mass of 4.0⋅g

Answer 2

Answer:

Avogadro's number of helium atoms has a mass of 4.0⋅g.

Explanation:

And Avogadro's number ≡ 6.022×1023⋅mol−1

Clearly, we have half a mole of helium atoms, so..

6.022×1023⋅helium atoms6.022×1023⋅helium atoms⋅mol−1=12⋅mol

And 12⋅mol

×4.00⋅g⋅mol−1

=2.00⋅g

The units cancel appropriately to give me an answer in grams as required.

This principle of equivalent mass, of the use of a number (the mole) to represent a given number of atoms or molecules, is absolutely fundamental to the study of chemistry. The problem is worth reviewing, because if you study chemistry, you will be doing a hell of a lot of problems like this.

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