What is the total mass of NO produced when 253 grams of copper react?
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
5.70 g
3.98 g
179 g
79.7 g
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d 79.7 gm will be answer
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1
3 mole Cu forms= 2 mole NO
3.9 mole(253÷63.5) CU fom= 2/3 ×3.98
= 7.96/3= 2.64 moles of NO
moles of NO=Given mass÷ molar mass
2.64 = mass÷ 30
so mass = 2.64×30
= 79.2
this is ur answer
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