what is the total no. of atoms present un 25mg of camphor
Answers
Answer:
Explanation:
Camphor chemical formula is C₁₀H₁₆O
Molecular mass of camphor is ( 10(12) + 16(1) + 16 ) g
= ( 120 + 16 + 16 ) g
= 152 g
25 mg = 0.025
No of moles of camphor in 25 mg of camphor = 0.025/152
≈ 0.000165
= 1.65 × 10⁻⁴ moles
No of atoms in 1.65 × 10⁴ moles = 1.65 × 10⁴ ×N₀
= 1.65 × 10⁻⁴ × 6.023 × 10²³
= 9.93795 × 10¹⁹
Explanation:
9.93×10^19........