What is the total number of atoms present in 25.0 mg of camphor C10H160?
(A) 9.89 x 1019 (B) 6.02 x 1020 (C) 9.89 x 1020 (D) 2.67 x 1021
Answers
Answered by
1
Answer:
Your correct answer is (D)2.67×1021
Answered by
0
Answer:
your correct answer is a) 9.89×1019
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