Question

What is the total number of electrons present in 4.6g of sodium?

Answer 1

Weight of sodium = 4.6 g
atomic weight of sodium = 23g/mol

number of mole of sodium = given weight/atomic weight
= 4.6/23 = 0.2

number of atom in sodium atom = number of mole of sodium × Avogadro's number
= 0.2 × 6.023 × 10²³
= 1.2046 × 10²³

we know, one sodium atom have 11 electrons
so, number of electrons present in 4.6g of sodium = 11 × 1.2046 × 10²³
= 13.2506 × 10²³
= 1.32506 × 10²⁴

Answer 2

Mole=4.6/23=0.2

0.2 × 6 × 10~23

1.2× 11× NA