What is the total number of ways of selecting 10 balls from unlimited supply of red , black and white and green balls ?
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Pikaa
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♦ Permutation Combination ♦
◘ We are basically counting for 40 balls, 10 each, instead of the 'unlimited' term which is somewhat meant for confusion
◘ Simplifying the problem, we seek for the positive integer solution for :
• Why ?
♦ Number of integral solutions of x₁ + x₂ + ... + xₐ = n is given as :
•
Hence, the solution subjects to finding : C( 10 + 4 - 1 , 4 - 1 ) = C( 13 , 3 )
◙ Finally, we have, the number of ways in which 10 four color balls can be selected out of unlimited stock is : 286
_____________________________________________________________
For further reference,
'https://www.careerbless.com/aptitude/qa/permutations_combinations_imp8.php'
'https://math.stackexchange.com/questions/411349'
_____________________________________________________________
Hope this helps
_____________________________________________________________
♦ Permutation Combination ♦
◘ We are basically counting for 40 balls, 10 each, instead of the 'unlimited' term which is somewhat meant for confusion
◘ Simplifying the problem, we seek for the positive integer solution for :
• Why ?
♦ Number of integral solutions of x₁ + x₂ + ... + xₐ = n is given as :
•
Hence, the solution subjects to finding : C( 10 + 4 - 1 , 4 - 1 ) = C( 13 , 3 )
◙ Finally, we have, the number of ways in which 10 four color balls can be selected out of unlimited stock is : 286
_____________________________________________________________
For further reference,
'https://www.careerbless.com/aptitude/qa/permutations_combinations_imp8.php'
'https://math.stackexchange.com/questions/411349'
_____________________________________________________________
Hope this helps
Anonymous:
10 each !?
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