Question

what is the total outside surface area of an open box of dimenson 10cmx8cmx2.5cm​

Answer 1

Given -

• Length of box = 10cm

• Breadth of box = 8cm

• Height of box = 2.5cm

To find -

• Total surface area of box.

Formula used -

• TSA of cuboid.

Solution -

In the question, we are provided with the dimensions of a cuboidal box, and we need to find the total surface area of that box. For that we will use the formula of TSA of cuboid. let's do it!

So -

TSA of cuboid = 2(lb + bh + hl)

where -

l = Length

b = Breadth

h = Height

On substituting the values -

TSA = 2(lb + bh + hl)

TSA = 2(10cm)(8cm) + (8cm)(2.5cm) +

(2.5cm)(10cm)

TSA = 2(80cm + 20cm + 25cm)

TSA = 2(125cm)

$\longrightarrow$ TSA = 250cm³

$\therefore$ The TSA of box is 250cm³

Other formule -

1. Lateral/curved surface area of cuboid = 2h(l + b)

2. Volume of cuboid = L × B × H

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Answer 2

Answer:

Given :-

• A box whose dimension is 10 cm × 8 cm × 2.5 cm.

To Find :-

• What is the total surface area or T.S.A.

Formula Used :-

★ T.S.A of Cuboid = 2(lb + bh + hl) ★

where,

• l = Length
• b = Breadth
• h = Height

Solution :-

Given :

• Length = 10 cm
• Breadth = 8 cm
• Height = 2.5 cm

According to the question by using the formula we get,

⇒ T.S.A = 2{(10 × 8) + (8 × 2.5) + (2.5 × 10)}

⇒ T.S.A = 2(80 + 20 + 25)

⇒ T.S.A = 2(100 + 25)

⇒ T.S.A = 2(125)

➠ T.S.A = 250 cm³

∴ The total surface area of an open box is 250 cm³.