What is the total pressure at the bottom of a column of liquid of density 1200kg/m3,if the height of the height of the column of the liquid is 8cm and the atmospheric pressure is 75cmHg.And the density of mercury is 13600
Answers
Answer:
Hydrostatic pressure = ϱgh
given ϱ=10
3
kg/m
3
1g=10ms
−2
,h=6m
Pressure = 10
3
m
3
kg
×10
s
2
m
×6
= 60000 P
a
Given info : The density of liquid which is poured in a column is 1200 kg/m³. the height of liquid in the column is 8 cm and the atmospheric pressure is 75 cm Hg and the density of mercury is 13600 kg/m³.
To find : the total pressure at the bottom of the column is ...
solution : total pressure at the bottom of the column is given as,
P = P₀ + ρgh
= ρ₀gh₀ + ρgh
= 13600 kg/m³ × 9.8 m/s² × 75 × 10¯² m + 1200 kg/m³ × 9.8 m/s² × 8 × 10¯²
= 136 × 9.8 × 75 + 12 × 9.8 × 8
= 100,900.8 N/m²
= 1.009008 × 10⁵ N/m²
≈ 10⁵ N/m²
Therefore the total pressure at the bottom of the column is 10⁵ N/m².
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