Question

What is the total resistance when two resistors having
resistance 612 and 992 are connected (i) in series and (ii)
parallel combination?

Answer 1

Answer:

Hey !

Here is your answer..

When these resistors are connected in series then :

Total resistance = R1 + R2

R = 612 + 992

R = 1604 ohm

When these resistors are connected in parallel then :

Total resistance = 1/R1 + 1/R2

R = 1/612 + 1/992

R = (248 + 153) / 151776

R = 401/151776

Thank u..

Hope it will be helpful..☺