Question

What is the total surface area of a cone having radius r/2 and height 21

Answer 1

hope it helps you my friend

Answer 2

The total surface area of cone is $\frac{22}{7} \times \frac{r}{2} \times \sqrt{21^2+(\frac{r}{2})^2}+\frac{22}{7} (\frac{r}{2})^2$

Step-by-step explanation:

Radius of cone = $\frac{r}{2}$

Height of cone = 21 cm

Total surface area of cone = $\pi r \sqrt{h^2+r^2}+\pi r^2$

Total surface area of cone =$\frac{22}{7} \times \frac{r}{2} \times \sqrt{21^2+(\frac{r}{2})^2}+\frac{22}{7} (\frac{r}{2})^2$

Hence The total surface area of cone is $\frac{22}{7} \times \frac{r}{2} \times \sqrt{21^2+(\frac{r}{2})^2}+\frac{22}{7} (\frac{r}{2})^2$

#Learn more:

The radius of the base of the cone is 9 cm and its height is 40cm.What is the curved surface area ??? what is it's total surface area???

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