what is the total surface area of a cone whose r = r/3 and slant height= 3L
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Answer:
The total surface are of the cone is \frac{\pi r(r+9l)}{9} 9πr(r+9l)
Given : Cone with radius \frac{r}{3} 3r
and slant height is 3l3l .
To find : The total surface area of cone ?
Solution :
Radius is \frac{r}{3} 3r
Slant height is 3l3l .
The total surface area of cone is given by,
TSA=\pi r(r+l)TSA=πr(r+l)
Substitute the values,
TSA=\pi \frac{r}{3}(\frac{r}{3}+3l)TSA=π 3r ( 3r +3l)
TSA=\pi \frac{r}{3}(\frac{r+9l}{3})TSA=π 3r( 3r+9l )
TSA=\frac{\pi r(r+9l)}{9}TSA= 9πr(r+9l)
Therefore, the total surface are of the cone is \frac{\pi r(r+9l)}{9} 9πr(r+9l)
.
Step-by-step explanation:
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