Question

what is the total surface area of a cuboid whose measures are as follows ...
height = 3 cm,
breadth = 5 cm,
length = 4 cm

Answer 1

Answer:

T. S. A of cuboid= 2(lb+bh+lh)

=2(4×5+5×3+3×4)

=2(20+15+12)

=2(47)

=94 cm²

Answer 2

$\sf\huge\bold{Solution}$

Given

Height of cuboid =3cm

Breadth of cuboid=5cm

Length of cuboid=4cm

To Find

Total surface area of cuboid

Total surface area is the total area occupied by a solid figure including its base + top surface.

Note :In curved surface area includes only curved surface means edges only not whole surface.

Total surface of cuboid is =2(lb+bh+hl)

Where l is length ,b is breadth and h is height

$= > 2(4 \times 5 + 5 \times 3 + 3 \times 4)$

$= > 2(20 + 15 + 12)$

$= > 2(47) = 94$

∴TSA of cuboid is 94cm²

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Further solved =>

Curved surface area of cuboid is =>2(l+b)h

=>2(4+5)×3=2(9)×3

=>54cm²

Volume of cuboid =lbh

=>4×5×3=60cm³