What is the total the distance travelled and the displacement covered by the object in 50s?
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Total distance travelled will be sum of all areas under the curve from 0 to 50.
Total distance = (10)(50) + (1/2) (10)(50) + (1/2)(10)(50) + (20)(50) = 500 + 250 + 250 + 1000 = 2000 m
And total displacement = 500 + 250 - 250 - 1000
= - 500 m or 500 m in negative direction
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Step-by-step explanation:
Answer for fourth part:
AB: object at rest
BD: -50-50
DE: Object at rest
Ans: 0+(-50)-50+0= -100
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