Question

What is the total volume of gases produced when 8.0 L of nitrogen trichloride (NCl3) decomposes into nitrogen and chlorine at a constant pressure and temperature?


2NCl3 (g) --> N2 (g) + 3Cl2 (g)

Answer 1

Answer:

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Answer 2

Given:

Volume of NCl3 = 8 L

To Find:

The total volume of gases produced upon the decomposition of nitrogen trichloride (NCl3) into nitrogen and chlorine.

Calculation:

- No of moles in 8 L NCl3 = 8/22.4 = 0.357 moles

- The decomposition reaction of NCl3 is given as:

2 NCl3 (g) → N2 (g) + 3 Cl2 (g)

⇒ 2 moles of NCl3 decomposes to give 1 mole N2 and 3 moles Cl2.

⇒ 1 mole of NCl3 decomposes to give 0.5 mole N2 and 1.5 moles Cl2.

⇒ 0.357 moles of NCl3 decomposes to give 0.1785 moles N2 and 0.5355 moles Cl2.

- Total moles of gases produced = 0.1785 + 0.5355 = 0.714

- Total volume of gases produced = 0.714 × 22.4 ≈ 16 L

- So, the total volume of gases produced upon the decomposition of 8 L nitrogen trichloride (NCl3) is 16 Litres.