Question

What is the transfer rate of an eight-track magnetic tape whose speed is 120 inches per second
and whose density is 1600 bits per inch?

Answer 1

The tape moves at a speed s = 120 inches/second

Density of tape = 1600 bits per inch.

Total number of tracks = 8.

Data transfer rate per each track = tape speed x Density of tape.

= 120 * 1600 = 192000 bits / second.

8 bits = 1 byte.

Hence Data transfer speed per track = 24000 Bytes / second.

Data transfer speed for 8 tracks = 24000 * 8 bytes / second.

= 192000 bytes / second = 192 KBytes / second. (∵ 1000 = 1 Kilo for speed calculation)