What is the transition of li+2 after absorption of light which undergo transition
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ANSWER
As we know that,
λ
1
=R
H
Z
2
(
n
1
2
1
−
n
2
2
1
)
For He
+
-
λ
1
=R
H
(2)
2
(
2
2
1
−
4
2
1
)
For Li
+2
-
λ
1
=R
H
(3)
2
(
n
1
2
1
−
n
2
2
1
)
Given that λ is same.
Therefore,
R
H
(3)
2
(
n
1
2
1
−
n
2
2
1
)=R
H
(2)
2
(
2
2
1
−
4
2
1
)
⇒(
n
1
2
1
−
n
2
2
1
)=(
3
2
1
−
6
2
1
)
Therefore,
n
1
=3
n
2
=6
Hence the transition is from n=6 to n=3.
December 20, 2019
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