Question

What is the transmittance if you measure the drink mix on the preset conditions at 508 nm and 100 mM?

Answer 1

$\huge\color{red} Answer$

The transmittance "T" of this sample is related to its absorbance "A". This absorbance is defined according to Beer's Law:

A

=

ϵ

×

l

×

c

where

ϵ

is the molar extinction coefficient of this light-absorbing solute at 508 nm, "l" is the path length and "c" is the molarity of the light-absorbing solute in the solution. We are not given the path length or the molar extinction coefficient, so we shall assume the following values:

Path length =

l

=

1.00

c

m

Molar extinction coefficient at 508 nm =

ϵ

=

1.00

M

−

1

c

m

−

1

Solute concentration (given) =

c

=

100

m

M

=

0.100

M

Therefore the absorbance and transmittance of the solution will be:

A

=

1.00

M

−

1

c

m

−

1

×

1.00

c

m

×

0.100

M

A

=

0.100

T

=

10

−

A

=

10

−

0.100

=

0.794

thank u ⭐