Question

What is the transport number of cation and anion having speed ratio value equal to 1? Answer A. 0.5 B. 0.4 c. O 0.2 D. 0.1​

Answer 1

Answer:

I don't know the exact answer but I think answer is A

Answer 2

Answer:

(A)The transport number of anion and cation is 0.5

Explanation:

Given that,the speed ratio value of anion and cation is one.We are required to find the transport number of both anion and cation based on their speed ratios.Let us assume that,

Speed of Anion=v

Speed of cation=u

Hence,according to the given question,the ratio is 1

⇒$\frac{v}{u} =1$

Now,the transport number of anion is the ratio of speed of anion to the sum of speeds of both anion and cation.Therefore,

$t_{a} =\frac{v}{u+v} =\frac{1}{\frac{v+u}{v} } =\frac{1}{1+\frac{u}{v} } =\frac{1}{1+1} =0.5$

Similarly,the transport number of cation is the ratio of speed of cation to the sum of speeds of both anion and cation.Therefore,

$t_{c} =\frac{u}{u+v} =\frac{1}{\frac{v+u}{u} } =\frac{1}{1+\frac{v}{u} } =\frac{1}{1+1} =0.5$

Therefore,the transport numbers of both anion and cation are obtained to be 0.5

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