What is the trick to find the 3 digit numbers divided by. 7?
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The Three digit number divisble by 7 :--
100 to 999 are total three digit numbers
so 100/3 == remaining 5 add to 100 it will become 105,,,
and now 999/5 == remaining 5 subtract from 999...
Now.
AP becomes 105, 112, 119 ......... 995.
Common difference is 7
First term is 105
Now you have to find last term..
![a + (n - 1)d a + (n - 1)d](https://tex.z-dn.net/?f=a+%2B+%28n+-+1%29d)
![105 + (n - 1)7 = 995 105 + (n - 1)7 = 995](https://tex.z-dn.net/?f=105+%2B+%28n+-+1%297+%3D+995)
![896 \div 7 = (n - 1) \\ 128 = (n - 1) \\ n = 129 896 \div 7 = (n - 1) \\ 128 = (n - 1) \\ n = 129](https://tex.z-dn.net/?f=896+%5Cdiv+7+%3D+%28n+-+1%29+%5C%5C+128+%3D+%28n+-+1%29+%5C%5C+n+%3D+129)
Here is your answer mark me brainliest if you like it !!!
100 to 999 are total three digit numbers
so 100/3 == remaining 5 add to 100 it will become 105,,,
and now 999/5 == remaining 5 subtract from 999...
Now.
AP becomes 105, 112, 119 ......... 995.
Common difference is 7
First term is 105
Now you have to find last term..
Here is your answer mark me brainliest if you like it !!!
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