what is the trick to split the middle term of x^2-169x+3600=0
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Given Equation is x^2 - 169x + 3600 = 0
x^2 - 144x - 25x + 3600 = 0
x(x - 144) - 25(x - 144) = 0
(x - 144)(x - 25) = 0
x - 144 = 0 = > x = 144
x - 25 = 0 = > x = 25.
Therefore the required values are 144 and 25.
Hope this helps!
x^2 - 144x - 25x + 3600 = 0
x(x - 144) - 25(x - 144) = 0
(x - 144)(x - 25) = 0
x - 144 = 0 = > x = 144
x - 25 = 0 = > x = 25.
Therefore the required values are 144 and 25.
Hope this helps!
ArvindYadav1:
Sorry to say that I know the answer but I want to understand the concept
Which concept Arvind.
how you arrived at 144 and 25
This question can be answered in many ways. One I already did.Another way is Using the quadratic equation -b+b^2-4ac/2a (or) -b - b^2-4ac/2a
any other way of reaching the conclusion regarding 144 and 25 ?
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