Question

what is the trigonometric formula for sec^2 - tan ^2 =? ​

Answer 1

Step-by-step explanation:

1-tan²∅= sec²∅

tan²∅-sec²∅= 1

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Answer 2

Answer:-

${sin}^{2} x + {cox}^{2} x = 1$

Hence:

${cox}^{2} x = 1 - {sin}^{2} x$

And we find that:

$= > {sec}^{2} x - {tan}^{2} x$

$= > \frac{1}{ {cox}^{2} x} - \frac{ {sin}^{2}x }{ {cox}^{2}x }$

$= > \frac{ {cox}^{2} x}{ {cox}^{2}x }$

$= 1$

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